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SOLUTII PARTEA I›ii...Din teorema sinusului avem sin B 100 — = 2R sin B = — 6. m(4A) + m(4B) + m(4C) = AB.BC.sinÐ 6-5.sin30' m (4B) = 15 SUBIECTUL 1 (30 de puncte) 1 G+2 G-2
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